Fundamentals of Electrical Engineering (4311101) - Winter 2023 Solution

Solution guide for Fundamentals of Electrical Engineering (4311101) Winter 2023 exam

Question 1(a) [3 marks]

Define Power & Energy.

Answer:

  • Power: Rate of doing work or energy consumption per unit time. Measured in Watts (W).
  • Energy: Ability to do work or the work done. Measured in Joules (J) or Watt-hours (Wh).

Table: Power vs Energy

ParameterDefinitionFormulaUnit
PowerRate of energy transferP = W/tWatt (W)
EnergyCapacity to do workE = P × tJoule (J) or Watt-hour (Wh)

Mnemonic: "Power Performs, Energy Endures"

Question 1(b) [4 marks]

Define current and electrical potential.

Answer:

Diagram:

  • Current: Flow of electric charge per unit time. Measured in Amperes (A).
  • Electrical Potential: Work done per unit charge to move a charge from one point to another. Measured in Volts (V).

Mnemonic: "Current Charges, Potential Pushes"

Question 1(c) [7 marks]

Explain KCL and KVL with examples.

Answer:

Diagram:

goat

Kirchhoff's Current Law (KCL):

  • Sum of currents entering a node equals sum of currents leaving it.
  • Example: At node X, i1 + i2 = i3

Kirchhoff's Voltage Law (KVL):

  • Sum of voltage drops around any closed loop equals zero.
  • Example: V1 - V(R1) - V(R2) = 0

Mnemonic: "Currents Come-Leave, Voltages Voyage-Loop"

Question 1(c) OR [7 marks]

Explain different types of connections for Resistors.

Answer:

Diagram:

Table: Series vs Parallel Connection

ParameterSeries ConnectionParallel Connection
Total ResistanceReq = R1 + R2 + R3 + ...1/Req = 1/R1 + 1/R2 + 1/R3 + ...
CurrentSame through all resistorsDivides through each path
VoltageDivides across resistorsSame across all resistors
ApplicationVoltage dividersCurrent division

Mnemonic: "Series Sum, Parallel Parts"

Question 2(a) [3 marks]

Define Resistance and Resistivity. Also state their unit of measurement.

Answer:

  • Resistance: Opposition to current flow, measured in Ohms (Ω). R = V/I.
  • Resistivity: Material property indicating resistance per unit dimension, measured in Ohm-meter (Ω·m). ρ = RA/L.

Mnemonic: "Resistance Restricts, Resistivity Relates to material"

Question 2(b) [4 marks]

Define cell and write names of different types of cell.

Answer:

Diagram:

goat
  • Cell: Device that converts chemical energy into electrical energy creating a voltage.

Types of Cells:

  1. Primary cells: Dry cell, Alkaline cell, Mercury cell
  2. Secondary cells: Lead-acid, Nickel-Cadmium, Lithium-ion

Mnemonic: "Primary Produces once, Secondary Serves repeatedly"

Question 2(c) [7 marks]

Calculate total equivalent resistance of the above circuit if R1=5Ω, R2=3Ω, R3=4Ω, R4=1Ω, R5=2Ω.

Answer:

Diagram:

goat

Step-by-step solution:

  1. R2 and R3 are in series: R23 = R2 + R3 = 3Ω + 4Ω = 7Ω
  2. R23 and R4 are in parallel: 1/R234 = 1/7 + 1/1 = (1+7)/7 = 8/7 Therefore, R234 = 7/8 = 0.875Ω
  3. R1, R234, and R5 are in series: Req = R1 + R234 + R5 = 5Ω + 0.875Ω + 2Ω = 7.875Ω

Therefore, equivalent resistance = 7.875Ω

Mnemonic: "Series-Sum, Parallel-Product over Sum"

Question 2(a) OR [3 marks]

Find the cost of energy if 100W bulb operated 10 hours daily for 30 days. Rate of energy is Rupees 5/unit.

Answer:

Table: Energy Calculation

ParameterValueCalculation
Power100W = 0.1kWGiven
Operating hours10 hours/day × 30 days = 300 hoursGiven
Energy consumed0.1kW × 300h = 30kWh = 30 unitsE = P × t
RateRs. 5/unitGiven
Total cost30 units × Rs. 5/unit = Rs. 150Cost = Units × Rate

Therefore, cost of energy = Rs. 150

Mnemonic: "Energy × Rate = Electric bill fate"

Question 2(b) OR [4 marks]

State ohm's law and explain the use ohm's law to calculate current in any circuit.

Answer:

Diagram:

Ohm's Law: Current flowing through a conductor is directly proportional to voltage and inversely proportional to resistance.

Formula: V = IR or I = V/R or R = V/I

Application: To find current in a circuit, measure voltage across a component and divide by its resistance (I = V/R).

Mnemonic: "Volts Invite current, Resistance Restricts"

Question 2(c) OR [7 marks]

Show that the current in a purely capacitive circuit leads the applied voltage by 90° and the current in a purely inductive circuit lags the applied voltage by 90°.

Answer:

Diagrams:

For Capacitive Circuit:

  • Voltage equation: v = V sin(ωt)
  • Current: i = C × dv/dt = ωCV cos(ωt) = I sin(ωt + 90°)
  • Current leads voltage by 90°

For Inductive Circuit:

  • Voltage equation: v = L × di/dt = ωLI cos(ωt) = V sin(ωt + 90°)
  • Current: i = I sin(ωt)
  • Current lags voltage by 90°

Mnemonic: "ELI the ICE man" - In EL (inductor), I lags E; in ICE (capacitor), I leads E

Question 3(a) [3 marks]

Define cycle, form factor and amplitude.

Answer:

Diagram:

goat
  • Cycle: One complete repetition of a waveform.
  • Form Factor: Ratio of RMS value to average value. For sine wave = 1.11.
  • Amplitude: Maximum displacement of a waveform from its mean position.

Mnemonic: "Cycles Complete, Form Factors Find ratio, Amplitude Achieves maximum"

Question 3(b) [4 marks]

Define RMS and Average value. Write expression of RMS and average value of sinusoidal waveform.

Answer:

Table: RMS vs Average Value

ParameterDefinitionFormula for Sine Wave
RMS ValueSquare root of mean of squared valuesVrms = Vm/√2 = 0.707 Vm
Average ValueMean of all instantaneous values over half cycleVavg = 2Vm/π = 0.637 Vm
  • RMS (Root Mean Square): Equivalent DC value that produces same heating effect.
  • Average Value: Mean of all instantaneous values over a half cycle.

Mnemonic: "RMS Relates to heating, Average Adds and divides"

Question 3(c) [7 marks]

Explain the terms Apparent power, True Power and Reactive power. State their unit of measurement.

Answer:

Diagram:

Table: Types of Power

Power TypeDefinitionFormulaUnit
Apparent Power (S)Total power suppliedS = VIVA (Volt-Ampere)
True Power (P)Actual power consumedP = VI cos φW (Watt)
Reactive Power (Q)Power oscillating between source and loadQ = VI sin φVAR (Volt-Ampere Reactive)

Power Triangle: S² = P² + Q²

Mnemonic: "Active Performs work, Reactive Returns energy, Apparent Adds vectors"

Question 3(a) OR [3 marks]

Write mathematical expressions of 3-phase voltages.

Answer:

Three-phase voltage expressions:

Table: 3-Phase Voltages

PhaseExpression
R-phaseVR = Vm sin(ωt)
Y-phaseVY = Vm sin(ωt - 120°)
B-phaseVB = Vm sin(ωt - 240°)

Where Vm is the maximum voltage and ω is the angular frequency.

Mnemonic: "Red phase Reference, Yellow lags 120°, Blue brings up 240°"

Question 3(b) OR [4 marks]

Define crest factor and state value of crest factor for sine wave.

Answer:

Diagram:

goat
  • Crest Factor: Ratio of peak value to RMS value of a waveform.
  • Formula: Crest Factor = Peak Value / RMS Value
  • For sine wave: Crest Factor = 1/0.707 = 1.414

Mnemonic: "Crest Compares peak to RMS"

Question 3(c) OR [7 marks]

Describe different three phase electrical connections.

Answer:

Diagram:

Table: Star vs Delta Connection

ParameterStar (Y) ConnectionDelta (Δ) Connection
Line Voltage (VL)√3 × Phase VoltageSame as Phase Voltage
Line Current (IL)Same as Phase Current√3 × Phase Current
Neutral WirePresentAbsent
ApplicationUnbalanced loads, ResidentialBalanced loads, Industrial

Mnemonic: "Star Shows neutral, Delta Delivers higher current"

Question 4(a) [3 marks]

Calculate the peak to peak value of a sinusoidal voltage if RMS value is 230V.

Answer:

Table: Calculation Steps

ParameterFormulaCalculation
RMS ValueGiven230V
Peak ValueVm = √2 × VrmsVm = √2 × 230 = 325.27V
Peak-to-Peak ValueVp-p = 2 × VmVp-p = 2 × 325.27 = 650.54V

Therefore, peak-to-peak value = 650.54V

Mnemonic: "RMS to Peak - multiply by √2, Peak to Peak - double it"

Question 4(b) [4 marks]

An alternating current is given by i=142.14sin628t find frequency and time period.

Answer:

Table: Calculation Steps

ParameterFormulaCalculation
Given equationi = 142.14 sin(628t)ω = 628 rad/s
Frequencyf = ω/(2π)f = 628/(2π) = 100 Hz
Time PeriodT = 1/fT = 1/100 = 0.01 s = 10 ms

Therefore, frequency = 100 Hz and time period = 0.01 s

Mnemonic: "Frequency From omega divide 2π, Time takes inverse"

Question 4(c) [7 marks]

State and explain Fleming's left hand rule and right hand rule.

Answer:

Diagram:

goat

Fleming's Left Hand Rule (Motor):

  • Used to determine direction of force on a current-carrying conductor in a magnetic field.
  • Hold left hand with thumb, fore and middle fingers at right angles.
  • Thumb: Motion (Force)
  • Forefinger: Magnetic field
  • Middle finger: Current

Fleming's Right Hand Rule (Generator):

  • Used to determine direction of induced current when a conductor moves in a magnetic field.
  • Hold right hand with thumb, fore and middle fingers at right angles.
  • Thumb: Motion of conductor
  • Forefinger: Magnetic field
  • Middle finger: Induced current

Mnemonic: "Left Lifts motors, Right Raises generators"

Question 4(a) OR [3 marks]

A conductor of length 1 metre moves with speed of 30m/s in magnetic field of 0.6 Tesla making angle of 30° with the field. Calculate dynamically EMF induced in it. (use sin 30°=0.5)

Answer:

Table: Given Parameters

ParameterValue
Length (l)1 meter
Speed (v)30 m/s
Magnetic Field (B)0.6 Tesla
Angle (θ)30°

Formula: E = Blv sin θ

Calculation: E = 0.6 × 1 × 30 × 0.5 = 9 volts

Therefore, induced EMF = 9 volts

Mnemonic: "EMF Emerges from Field, velocity and Length with angle"

Question 4(b) OR [4 marks]

State & explain Lenz's law.

Answer:

Diagram:

goat

Lenz's Law: The direction of induced EMF or current is always such that it opposes the cause that produces it.

Application: When a magnet approaches a coil, induced current creates a magnetic field that repels the approaching magnet.

Mnemonic: "Lenz Likes to Oppose"

Question 4(c) OR [7 marks]

Explain Statically and dynamically induced EMF.

Answer:

Table: Statically vs Dynamically Induced EMF

ParameterStatically Induced EMFDynamically Induced EMF
DefinitionEMF induced due to change in current/fluxEMF induced due to movement of conductor in magnetic field
Physical actionFixed conductor, changing fieldMoving conductor in fixed field
ExampleTransformerGenerator
Formulae = -N dΦ/dte = Blv sin θ

Mnemonic: "Static Stays but flux Changes, Dynamic Drives through field"

Question 5(a) [3 marks]

Explain PV Cell.

Answer:

Diagram:

goat
  • PV Cell: Device that converts sunlight directly into electricity using photovoltaic effect.
  • Working: Sunlight excites electrons in semiconductor material, creating voltage difference.
  • Material: Typically made from silicon with P-N junction.

Mnemonic: "Photons Visit, Current Created"

Question 5(b) [4 marks]

Explain the solar PV panel and arrays.

Answer:

Diagram:

Table: Solar System Hierarchy

ComponentDescription
PV CellBasic unit that converts sunlight to electricity (0.5V - 0.6V)
PV PanelMultiple cells connected in series/parallel (typically 12V, 24V)
PV ArrayMultiple panels connected to achieve required voltage/current

Mnemonic: "Cells Combine into Panels, Panels Produce Arrays"

Question 5(c) [7 marks]

Draw and explain block diagram of wind power system.

Answer:

Diagram:

Components of Wind Power System:

  1. Wind Turbine: Converts wind energy to mechanical energy
  2. Gearbox: Increases rotational speed for generator
  3. Generator: Converts mechanical energy to electrical energy
  4. Power Electronics: Controls and regulates electrical output
  5. Transformer: Steps up/down voltage for transmission/distribution
  6. Control System: Monitors and optimizes overall operation

Mnemonic: "Wind Turns Gears, Generating Electrical Returns"

Question 5(a) OR [3 marks]

State the benefits of green energy.

Answer:

Table: Benefits of Green Energy

Benefit CategoryExamples
EnvironmentalReduces pollution, Minimizes carbon footprint
EconomicCreates jobs, Reduces energy dependency
HealthImproves air quality, Reduces health issues
SustainabilityRenewable, Inexhaustible sources

Mnemonic: "Clean Energy Creates Economic Salvation"

Question 5(b) OR [4 marks]

Explain Solar PV applications in brief.

Answer:

Diagram:

Solar PV Applications:

  1. Residential: Rooftop systems, Solar water heaters
  2. Commercial: Building integrated PV, Solar parking
  3. Industrial: Process heating, Power generation
  4. Utility Scale: Solar farms, Grid support
  5. Off-grid: Rural electrification, Remote applications

Mnemonic: "Residences, Commerce, Industry Utilize Solar"

Question 5(c) OR [7 marks]

Explain different types of Green energy.

Answer:

Table: Types of Green Energy

TypeSourceApplications
SolarSunPV systems, Thermal plants
WindMoving airWind turbines, Windmills
HydroFlowing waterDams, Run-of-river systems
BiomassOrganic matterCombustion, Biogas production
GeothermalEarth's heatDirect heating, Power plants
TidalOcean tidesBarrage systems, Tidal turbines

Diagram:

Mnemonic: "Sun, Wind, Hydro, Biomass, Geothermal, Tidal - Simple Ways Humans Build Green Tomorrow"