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title: 'Lecture 35: Emitter follower circuit'
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  ## DI02011011: Electronics Circuit and Application (ECA)
  Feedback in amplifiers
---

# DI02011011: Electronics Circuit and Application (ECA)
## Lecture 35: Emitter follower circuit
### Feedback in amplifiers

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Welcome to Lecture 35. Today we analyze the Emitter Follower (Common Collector) circuit, one of the most widely used buffer configurations in analog electronics.
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# Lecture Agenda: Emitter Follower Circuit Breakdown

- Circuit Topology & DC Biasing Analysis ($V_B, V_E, I_E, r_e$)
- Identification of 100% Voltage-Series Feedback Mechanism ($\beta = 1.0$)
- Small-Signal Hybrid-\pi$ AC Equivalent Circuit Modeling
- Exact Mathematical Derivation of Voltage Gain ($A_v = \frac{R_E'}{r_e + R_E'}$)
- Exact Mathematical Derivation of Input Impedance ($R_{in} = R_B \parallel [r_\pi + (1+\beta_0)R_E']$)
- Exact Mathematical Derivation of Output Impedance ($R_{out} = R_E \parallel [r_e + \frac{R_S'}{1+\beta_0}]$)
- Current Gain ($A_i \approx \beta_0$) and Power Gain ($A_p \approx \beta_0$) Analysis
- High-Frequency Response & Absence of Miller Effect Multiplication
- Solved Numerical Problem: Complete DC & AC Emitter Follower Analysis
- Practical Application: High-Impedance Sensor Buffer Design
- Large-Signal Drive Limitations & Asymmetrical Cutoff Clipping
- Summary & Key Engineering Takeaways

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Our agenda covers topology identification, feedback classification, AC derivations for Av, Rin, Rout, Ai, high-frequency response, numerical examples, and buffer applications.
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# Circuit Topology & DC Operating Point Analysis

- Circuit Configuration: Collector connected directly to $V_{CC}$ (AC ground), input signal $V_i$ applied to Base, output signal $V_o$ taken from Emitter across resistor $R_E$.
- Base Voltage DC Bias: Voltage divider biasing gives DC Base voltage $V_B = V_{CC} \frac{R_2}{R_1 + R_2}$.
- Emitter DC Voltage & Current: Emitter DC voltage $V_E = V_B - V_{BE} = V_B - 0.7\text{ V}$. DC Emitter current $I_E = \frac{V_E}{R_E}$.
- Dynamic Emitter Resistance ($r_e$): $r_e = \frac{V_T}{I_E} = \frac{26\text{ mV}}{I_E}$. Base-emitter dynamic resistance $r_\pi = (1 + \beta_0) r_e$.

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The Emitter Follower has its collector connected to VCC (AC ground). Input is applied to the base, and output is taken from the emitter. DC biasing sets emitter current I_E.
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# Feedback Topology: 100% Voltage-Series Feedback

- Feedback Signal Sampling: Output voltage $V_o = V_E$ is sampled directly at the emitter.
- Series Feedback Injection: 100% of output voltage $V_o$ is fed back in series opposition to base input $V_i$: $v_{be} = v_i - v_o = v_b - v_e$.
- Feedback Ratio: $\beta = 1.0$ ($100\%$ voltage-series negative feedback).
- Closed-Loop Gain Formulation: Open-loop gain $A_v = g_m (R_E \parallel r_o) \gg 1$. Closed-loop voltage gain $A_{vf} = \frac{A_v}{1 + 1 \cdot A_v} = \frac{A_v}{1 + A_v} \approx 1.0$ V/V.

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The Emitter Follower is a 100% voltage-series feedback amplifier. Because beta = 1.0, closed-loop gain A_vf = Av / (1 + Av), which is slightly less than unity.
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# Small-Signal Hybrid-\pi$ AC Equivalent Circuit Model

- AC Model Representation: Replace BJT with hybrid-\pi$ model featuring base-emitter resistance $r_\pi$, dependent current source $g_m v_\pi = \beta_0 i_b$, and output load $R_E' = R_E \parallel R_L$.
- Input Voltage Loop Equation: $v_i = v_\pi + v_o = i_b r_\pi + i_e R_E'$.
- Emitter AC Current Relationship: $i_e = i_b + \beta_0 i_b = (1 + \ensuremath{\beta}_0) i_b$.
- Output Voltage Equation: $v_o = i_e R_E' = (1 + \beta_0) i_b R_E'$.

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Draw the small-signal hybrid-pi model. Input voltage v_i splits across r_pi and output voltage v_o. Total emitter current i_e is (1 + beta0) * i_b.
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# Exact Derivation of Voltage Gain ($A_v$)

- Gain Definition: $A_v = \frac{v_o}{v_i} = \frac{(1 + \beta_0) i_b R_E'}{i_b r_\pi + (1 + \beta_0) i_b R_E'} = \frac{(1 + \beta_0) R_E'}{r_\pi + (1 + \beta_0) R_E'}$.
- Simplification with $r_e$: Divide numerator and denominator by $(1 + \beta_0)$, substituting $r_e = \frac{r_\pi}{1 + \beta_0}$:
- Final Voltage Gain Formula: $A_v = \frac{R_E'}{r_e + R_E'}$, where $R_E' = R_E \parallel R_L$.
- Gain Characteristics: Since $R_E' \gg r_e$ (typically $R_E' \approx 1\text{ k}\Omega - 10\text{ k}\Omega$ vs $r_e \approx 5 - 25\ \Omega$), $A_v$ is positive (in-phase output, $0^\circ$ phase shift) and slightly less than unity ($0.98 - 0.999$).

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This derivation is extremely elegant. Dividing by (1 + beta0) converts the equation to Av = R_E' / (r_e + R_E'). Since R_E' is much larger than r_e, gain is just under 1.
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# Exact Derivation of Input Impedance ($R_{in}$)

- Base Input Impedance ($R_{in,base}$): $R_{in,base} = \frac{v_i}{i_b} = \frac{i_b r_\pi + (1 + \beta_0) i_b R_E'}{i_b} = r_\pi + (1 + \beta_0) R_E'$.
- Resistance Reflection Rule: Emitter resistance $R_E'$ reflected back into the base loop is multiplied by factor $(1 + \beta_0)$.
- Total Stage Input Impedance ($R_{in}$): Including bias resistors $R_B = R_1 \parallel R_2$:
- Final Input Impedance Formula: $R_{in} = R_B \parallel R_{in,base} = R_B \parallel \left[ r_\pi + (1 + \beta_0)(R_E \parallel R_L) \right]$. Reaches hundreds of $k\Omega$ to $M\Omega$.

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Notice the resistance reflection rule: any impedance in the emitter appears multiplied by (1 + beta0) when viewed from the base, boosting base input impedance into the megaohm range.
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# Exact Derivation of Output Impedance ($R_{out}$)

- Test Source Setup: Deactivate source ($v_s = 0\text{ V}$), apply test voltage $v_x$ at emitter port, measure test current $i_x$.
- Base Loop Equation: $i_b = -\frac{v_x}{r_\pi + (R_S \parallel R_B)}$, where $R_S' = R_S \parallel R_B$.
- Emitter Test Current: $i_x = -i_b - \beta_0 i_b + \frac{v_x}{R_E} = v_x \left[ \frac{1 + \beta_0}{r_\pi + R_S'} + \frac{1}{R_E} \right]$.
- Final Output Impedance Formula: $R_{out} = \frac{v_x}{i_x} = R_E \parallel \left[ \frac{r_\pi + R_S'}{1 + \beta_0} \right] = R_E \parallel \left[ r_e + \frac{R_S \parallel R_B}{1 + \beta_0} \right]$. Yields extremely low output impedance ($10\ \Omega - 50\ \Omega$).

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To find output impedance, apply test voltage v_x at the emitter with v_s = 0. Source and base resistors are divided by (1 + beta0) when reflected to the emitter, yielding low R_out.
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# Current Gain ($A_i$) & Power Gain ($A_p$) Derivation

- Transistor Current Gain: $A_{i,transistor} = \frac{i_e}{i_b} = 1 + \beta_0 \approx \beta_0$ (typically $100 - 300$).
- Stage Current Gain ($A_{is}$): Accounting for bias divider splitting and load splitting:
- Stage Current Gain Formula: $A_{is} = \frac{i_L}{i_s} = A_{i,transistor} \cdot \frac{R_B}{R_B + R_{in,base}} \cdot \frac{R_E}{R_E + R_L}$.
- Power Gain ($A_p$): $A_p = A_v \cdot A_{is} \approx 1.0 \cdot A_{is} \approx \beta_0$. Although voltage gain is unity, the Emitter Follower provides high power gain driven entirely by current amplification!

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Even though voltage gain is near 1, current gain is roughly beta0 (100 to 300). Therefore power gain A_p = Av * Ai is roughly beta0, providing significant power amplification.
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# High-Frequency Response & Absence of Miller Effect

- Miller Effect Review: In Common-Emitter stages, base-collector capacitance $C_\mu$ is multiplied by $(1 + |A_v|)$, creating large input Miller capacitance $C_{in,M} = C_\mu (1 + A_v)$.
- Common Collector Immunity: In Emitter Follower, Collector is AC grounded. Base-to-Collector voltage equals base voltage $v_b$, so $C_\mu$ is NOT multiplied by voltage gain ($A_{v,BC} = 0$).
- Base-Emitter Capacitance Bootstrapping: Base-to-emitter voltage is $v_{be} = v_i(1 - A_v) \approx 0$. Effective $C_\pi$ input capacitance is bootstrapped down to $C_{\pi,in} = C_\pi (1 - A_v) \ll C_\pi$.
- Ultra-Wide Bandwidth: Complete absence of Miller multiplication grants the Emitter Follower exceptionally high bandwidth, ideal for high-speed line drivers.

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The Emitter Follower is immune to the Miller effect because its collector is AC grounded. Furthermore, C_pi is bootstrapped by (1 - Av) approx 0, resulting in ultra-wide bandwidth.
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# Numerical Problem: Complete AC & DC Emitter Follower Analysis

- Given Parameters: $V_{CC} = 15\text{ V}$, $R_1 = 33\text{ k}\Omega$, $R_2 = 33\text{ k}\Omega$, $R_E = 3.3\text{ k}\Omega$, load $R_L = 1\text{ k}\Omega$, source $R_S = 600\ \Omega$, transistor $\beta_0 = 150$, $V_{BE} = 0.7\text{ V}$.
- Step 1 - DC Analysis: $V_B = 15 \times \frac{33k}{66k} = 7.5\text{ V}$. $V_E = 7.5 - 0.7 = 6.8\text{ V}$. $I_E = \frac{6.8\text{ V}}{3.3\text{ k}\Omega} = 2.06\text{ mA}$. Dynamic resistance $r_e = \frac{26\text{ mV}}{2.06\text{ mA}} = 12.62\ \Omega$. $r_\pi = (151) \times 12.62 = 1.905\text{ k}\Omega$.
- Step 2 - Voltage Gain ($A_v$): $R_E' = 3.3k \parallel 1k = 767.4\ \Omega$. $A_v = \frac{767.4}{12.62 + 767.4} = 0.9838\text{ V/V}$.
- Step 3 - Input Impedance ($R_{in}$): $R_{in,base} = 1.905k + (151 \times 767.4) = 117.78\text{ k}\Omega$. $R_B = 33k \parallel 33k = 16.5\text{ k}\Omega$. $R_{in} = 16.5k \parallel 117.78k = 14.47\text{ k}\Omega$.
- Step 4 - Output Impedance ($R_{out}$): $R_S' = R_S \parallel R_B = 600 \parallel 16.5k = 578.9\ \Omega$. $R_{out} = 3.3k \parallel \left[ 12.62 + \frac{578.9}{151} \right] = 3.3k \parallel [12.62 + 3.83] = 3.3k \parallel 16.45 = 16.37\ \Omega$!

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Walk through each step of this numerical problem: DC bias gives IE = 2.06 mA, re = 12.62 ohms. AC analysis yields Av = 0.9838 V/V, Rin = 14.47 k-ohms, and Rout = 16.37 ohms.
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# Practical Application: High-Impedance Sensor Buffer Design

- Problem Scenario: A piezoelectric transducer with high source impedance $R_S = 100\text{ k}\Omega$ drives a low impedance load $R_L = 100\ \Omega$. Compare direct connection versus inserting an Emitter Follower buffer ($R_{in} = 500\text{ k}\Omega$, $R_{out} = 10\ \Omega$, $A_v = 0.99$).
- Direct Connection Signal Voltage: $V_L = V_S \frac{R_L}{R_S + R_L} = V_S \frac{100}{100,000 + 100} = 0.000999 V_S$ ($99.9\%$ of signal LOST due to loading!).
- Buffered Connection Signal Voltage:
- Input voltage $V_{in} = V_S \frac{R_{in}}{R_S + R_{in}} = V_S \frac{500k}{600k} = 0.8333 V_S$.
- Output voltage $V_L = A_v V_{in} \frac{R_L}{R_{out} + R_L} = (0.99)(0.8333 V_S) \frac{100}{10 + 100} = 0.750 V_S$.
- Performance Gain: Signal voltage transfer restored from $0.1\%$ to $75.0\%$ — a $750$-fold improvement in voltage delivered to the load!

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This practical buffer example illustrates the power of impedance matching. Direct connection loses 99.9% of the signal voltage. Inserting an Emitter Follower delivers 75% of the signal voltage!
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# Limitations of Emitter Follower: Cutoff & Clipping

- Asymmetrical Drive Capability: Emitter follower can source large transient currents (transistor turns ON hard), but sinking current is strictly limited by DC bias current $I_E = \frac{V_E - V_{EE}}{R_E}$.
- Negative Swing Cutoff Clipping: On large negative input voltage swings, if load current demand $\frac{\Delta V}{R_L} > I_E$, transistor cuts off completely ($I_C = 0$), clipping the negative waveform.
- Complementary Push-Pull Solution: Replace single transistor and resistor $R_E$ with NPN-PNP complementary pair (Class-AB Emitter Follower).
- Push-Pull Advantage: NPN transistor sources positive load current; PNP transistor sinks negative load current, achieving symmetrical drive capability.

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A major limitation of the single transistor Emitter Follower is asymmetrical drive capability. Large negative swings can cut off the transistor. The complementary push-pull topology solves this.
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# Summary & Key Takeaways: Emitter Follower Circuit

- Voltage Gain & Phase: Near-unity voltage gain ($A_v = \frac{R_E'}{r_e + R_E'} \approx 0.98 - 0.999$), non-inverting ($0^\circ$ phase shift).
- Impedance Transformation: High input impedance ($R_{in} = R_B \parallel [r_\pi + (1+\beta_0)R_E']$) and low output impedance ($R_{out} = R_E \parallel [r_e + \frac{R_S'}{1+\beta_0}]$).
- Feedback & Bandwidth: Operates as 100% voltage-series feedback amplifier ($\beta = 1.0$), immune to Miller multiplication, yielding ultra-wide bandwidth.
- Buffer Application: Ideal impedance matching buffer bridging high-impedance sensors and low-impedance loads.

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To summarize, the Emitter Follower is a unity-gain voltage buffer providing high input impedance, low output impedance, high current gain, and ultra-wide bandwidth.
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